• Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off
Reading...
Front

Card Range To Study

through

image

Play button

image

Play button

image

Progress

1/19

Click to flip

Use LEFT and RIGHT arrow keys to navigate between flashcards;

Use UP and DOWN arrow keys to flip the card;

H to show hint;

A reads text to speech;

19 Cards in this Set

  • Front
  • Back
What is an isotope?
An atom with the same atomic number as another but with a different mass number.
Why do isotopes have the same chemical properties?
They have the same electronic structure.
What is the RAM or Ar?
The weighted average mass of an element. Itt is measurement on a scale which the carbon-12 atom has a mass of exactly 12 units.
What is a mole?
A measure of amount of substance.
What is the Avogadro number?
The number of atoms in 12g of carbon-12. It is about 6.02 x10 [23]
How do you calculate the RAM of an element using the relative abundances of its isotopes? (3)
Multiply each % with its relative mass
Add them all together and divide by 100
This gives you a weighted average of the RAM
Moles =
Mass/RAM
Describe how to obtain the formulae of simple compounds experimentally.
Find mass of each element
Divide each by its RAM
Divide both by the smallest to give ratio
What is water of crystallization?
The water associated with a salt when it is a hydrated solid
How do you indicate the number of moles of water of crystallization?
A dot followed by a number and the formula for water
What is the empirical formula?
It is the simplest formula made up from the ratio of the elements
How do you find the molecular formula from the molecular mass?
Take the empirical formula
Find the empirical formula mass
Divide the molecular mass by the empirical formula mass
Take this to be 'n'
Multiply the empirical formula by 'n'
How do you deduce the masses of reactants needed and the mass of product formed?
The total mass of starting materials will be equal to the mass of the products.
Moles of a gas =
Volume/24,000
One mole of any gas occupies ....
24dm(3) at rtp
1dm = ...cm
1cm(3) = ... cm(3)
1dm = 10cm
1cm(3) = 1000cm(3)
Moles of a solution =
Concentration x volume
Unit of concentration is
moles per decimeter cubed
How do you calculate the % yield?
Actual yield/expected yield x 100