Problem 1.17 In problem 1.17, the average age of pinon trees in the coast ranges of California was investigated. 500 ten-hectare plots randomly selected using a computer. The age of every pinon tree within each plot was measured and the average age of the plot was used as the unit measurement (Whitlock and Schluter, 2015, pg 20). The results of this investigation were used to estimate the average age of California pinon pines, making the population of interest in this study is all California…
the blue Skittles are .498, .488, .542, .526, and .441. The statistics for these numbers are .499 for the mean, .498 for the median, no mode, .0389 for the standard deviation, and .499 ± .0389 for the best answer. The Rf values for the dyes of the green skittles are .621, .455, .628, .590, and .397. The statistics for these numbers are .538 for the mean, .590 for the median, no mode, .105 for the standard deviation, and .538 ± .105 for the best answer. The Rf values for the dyes of the…
Equation of trendline 1 calculation: m= rise/run = 12/15 = 0.8 c= 5.9 y= 0.8x + 5.9 Equation of trendline 2 calculation: m= rise/run = 25/45 = 0.5 c= 17.6 y= 0.5x +17.6 Point of intersection: Equate both trendlines to find point of intersection 0.8x + 5.9 = 0.5x + 17.6 x= 39 Since x=39, x2= 9 as x2 represents x in descending order. R2: R2 for trendline 1 = 0.98 Correlation coefficient for trendline 1= 0.96 R2 for trendline 2 = 0.98 Correlation coefficient for trendline 2= -0.99 Ratio…
channels of 8 bit information. Thus, the pixel values vary from 0 to 255. Small training areas of around 300 pixels were selected from different land cover types from these 3 channels and also from the texture channels. Statistical data like Mean, Median and Standard Deviation is calculated and based on that, following conclusions were made. Numbe r of pixels 310 56 56.63 13.61 14.00 89.00 0 15 mean value Channe l 1: 6 July Channe 310 44 45.41 12.45 9.00 74.00 0 15 l 2…
Fig. (3-23) Extrapolate Resonance frequency (fo) map of Nile Delta Area Fig (3-24) is extrapolate contour map for Associated Amplification of ground motion (Ao) of Nile Delta Area , from this map we notice the following : A - The value of (Ao) in the Central, Eastern and Northern part of Nile Delta is the same in most points and varied from 4 to 5. B - The value of (Ao) in the North Western part of Nile Delta and Alexandria is the same in most points and varied from 5 to 7 and…
Lemma: If p > 3 is prime, then either p = 1 (mod 6) or p = 5 (mod 6). Proof: The residue classes modulo 6 partition Z, so any z in Z satisfies a congruence z = n (mod 6) where n is in {0,1,...,5}. z is divisible by 6 if n = 0, 2 if n = 2, 3 if n = 3, and 2 if n = 4. These cases cover the primes z = 2 and z = 3; if z > 3 is prime, it follows that n = 1 or n = 5, i.e., z = 1 (mod 6) or z = 5 (mod 6). Now suppose there are only finitely many primes congruent to 5 modulo 6, say p_1, ...,…
Descriptive statistics I can describe the data with the help of descriptive statistics. The data can be described with the help of various types of graphs and central tendency. Measures of central tendency are mean, median and mode. Mean is reliable for normal data. Median is reliable for a data which has outliers. And mode is preferred when data is categorical. There are various types of graphs like pie chart, bar graph which gives us a pictorial representation of data. Measure of…
A nerve cell is also called a motor neuron, which is made from a cell body, an axon and axon terminals. The cell body contains a nucleus and dendrites that receive the signals and send it down the axon that is covered in myelin sheath. The axon terminals are…
smoking. Although, at the same time the drug is killing nerve cells in the brain because it has strong toxins that it can damage the nerve cells and kill them. By continuously smoking, people keep damaging their nerves cells and over time at some point they would hit in a stage that it would change their lives forever. One of the worst case scenarios is that a person can get into a vegetative state and never recover from it because the nerve cells can’t recover never again in their lives.…
The class I observed was a senior exercise class on YouTube, https://www.youtube.com/watch?v=m7zCDiiTBTk. After watching the class, I can only assume the age of the participants is around 70 or 80 years of age. This class had 5 female participants and all of them stay seated throughout the entire class. The reason that the class participants are seated in chairs while exercising is because they may have limited mobility. Because of their age seniors need approach everything differently in life…