Question 1: a) A: Promoter B: Splice site C: 5’ UTR D: Start codon E: Stop codon F: 3’ UTR b) The sum of the exons and introns (all in kilobases) (1.2+8+0.7+27+0.4+11+3.1) = 51.4 kb. c) The sum of the exons (all in kilobases) (1.2+0.7+0.4+3.1) = 5.4 kb.…
b. When measuring the resistance value with the Avo 8, possible reasons for varience include a parallax error (not looking at the reading from directly above the meter), a reading error due to less divisions when measuring resistance, or the device not being properly zeroed. When measuring current, there are also fewer division, parallax is still a potential issue, and finally, incorrect zeroing of the meter. Voltage has an additional error, the loading of the meter itself. Alongside this issue, there is also parallax, zero, and accuracy/divisions.…
Lower Sample Rate (22,050 SR, 128 kbps): 8/10 Since there was some slight static, we gave the sample a 8/10. This could have occurred because of the rustling of the recorders jacket. Since the phone was placed close to the recorder, this sound could have been easy to pick up by the recording device. I think if we were able to listen to the recording with headphones, it would have been a more accurate depiction of the quality. There was some breathing and wind sound that could be heard in the background noise, especially in the rainbow passage reading.…
* For the first one this is what I would do... okay so we have the original equation for the first one & based off that this is what I would do... I would discover f ( 2 ) by inserting x equals 2. f…
Reply: We corrected it, and thanks again to read very explicitly. 7: You asked to correct "after allowing the GOST to expand vertically by suddenly turning off the EW"->"after allowing atoms from the GOST to expand vertically by suddenly turning off the EW" Atomic clouds expand, not the trap. Reply:…
noshort =1 Term - Regression Results ans = 0.0078 1.0945 -0.0000 -0.1332 -0.1963 -2.0644…
Lab #5: Introduction to Metasploit on Kali Linux Team: CRYPTERS 1 d. Why is it usually a bad idea to operate in the Linux environment as root? If you are unfamiliar with the concept of the root user, do a quick google search. It is always a good practice on any operating system to run your applications on a user level and leave the administrative tasks to the root user, and only on a per-need basis. Applications are meant to be run by users with non-administrative privileges.(Power December 4, 2010)…
Concurrency loss due to IO path critical sections (IPCS) Time lost in waiting queue (WT) to enter a critical section affects an application concurrency (AC), and impedes the application performance from scaling (AC ∝ 1 / WT) if a workload is bursty and highly parallelized. It is apparent that the wait time to enter a critical section is a function of the CS’s size (CSS) and the number of waiting threads (NWT) i.e. WT ∝ CSS * NWT. Furthermore, the work done (IO completed) is proportional to the trips made through the CSSs (i.e. IOs completed ∝ NWT). Therefore, existence of CSSs in IO path, high wait time, and large CSS’s size affects an application concurrency, and demands the measures to minimize their effects.…
Goals According to the flow chart above, we need to generate a binary sequence of 0's and 1's, the length of which is 2N bits, that occur with equal probability and are mutually independent for which a ‘rand’ function is used. The data is then passed through a QPSK modulator to produce N complex symbols of {±1 , ±1j}. At the receiver, noise is added to the transmitted signal and the resultant signal is then passed through the QPSK demodulator to produce estimates of the transmitted binary data. After that, the demodulator output is compared with the original sequence, and finally an error counter is used to count the number of bit errors.…
1. (8pts) From these data, graph your mean arterial pressure (MAP; see formula) and heart rate (y axes) vs. workload (in METS) on the x-axis (include resting results). Using this information, answer the following questions. Show ALL work. MAP…
At -50℃, or 223 K, the pressure was found to be 72.81 kPa. At 200℃, or 473 K, the pressure was found to be 154.44 kPa. These values were also calculated using the equation of the trendline from the graph, to predict a more accurate value. The equation y= mx+b was used to calculate this value, where y was the pressure in kilo Pascals, m was 0.2735 kPa/K, the slope of the trendline, x was the temperature in Kelvin, and b was 17.39 kPa, the y-intercept of the trendline.…
Purpose The purpose of the lab is to design an experiment to verify the spring constant for an unknown spring, also known as k, how much a spring resists change (compression or expansion). We used a method changing a mass and measured the change in x. Theory Free Body Diagram a=0 Legend: ¬¬ a-acceleration Sp-Spring N-Normal S-Surface E-Earth C-Cart G-Gravity…
In this lab I examined and drew different samples of slides and then categorized these slides into a logical evolutionary order. The first sample that most likely came first in the evolutionary order is the typical bacteria, which I viewed at a 1000 magnification. These bacteria can be found in the Eubacteria domain and kingdom. The bacteria in my sample were coccus, which means that the bacterium has a round shape, and this type of bacteria is one of the simplest forms of bacteria. These cells are also prokaryotic because they do not have a nucleus and they are heterotrophic because they do not produce their own food.…
1ml per sample. The samples were incubated at 4⁰C overnight. The following day, the samples were washed with DPBS at 4⁰C and then washed with 2ml 1 perm buffer twice. Anti-mouse Foxp3- PE Ab was added in a 1:100 dilution for 30 mins at 4⁰C. The samples were washed with perm buffer and resuspend in DPBS for flow cytometry analysis.…
The shape of the system at point 1 and 2 are labeled and shown below (Figure 5.12). The moment of the system was solved for in ABAQUS and superimposed in red over the shape of the column. It can be seen that the system moment is zero in a variety of places over the course of the loading. One place the moment it zero here is at L/2. The moment at L/2 is only zero during line-contact.…