The term is commonly used in nuclear physics to describe how quickly unstable atoms or how long stable atoms survive, radioactive decay. The term is also used more generally to characterise any type of exponential or non-exponential decay. For example, the medical sciences refers to the biological half-life of drugs and other chemicals in a human body. The converse of half-life is doubling time (Wikipedia). In this project, the concept of exponential is explored. We will apply the natural logarithm/Neperian to solve our problem. The natural logarithm of a number is its logarithm to the base of the mathematical constant e. Where e is an irrational number approximately equal to …show more content…
It is one of the most hazardous of the radioactive isotope of the chemical element Strontium. It is formed in nuclear reactors or during the explosion of nuclear weapons. Strontium has severe effects on the growth of young animals than in adults. 90Sr has a half-life of 29 years and it is believe that about 500g is present in the environment of the United States. Using this scenario, we are trying to determine how long it will take the substance strontium 90 to disappear?. In order to find the answer to that question, we will start by determining the amount of Strontium 90 after 150 years, 200 years and 300 years. We will then write an equation to represent the problem. Then we will find out how long it will take the substance to decay to 5g and to 0.0011875 g. Once we get the answers to these questions,we will answer the main question in our investigation. The goal of this project is to determine how long will it take the substance strontium 90 to disappear?. However, this question can not be directly answered. We will first determine the amount of Strontium-90 after 150 years, 200 years and 300 years. Then, we will write an equation to represent the problem. After that, we will find out how long will it take for the mass of the substance to decay to 5g and 0.0011875g given that the substance has a half-life of 29 years. When all these sub-questions will be answered, we will