Genetic Analysis in Plants
Trev Mumm and Peter Masinelli
Life 120 – Lab Section 122
April 28th, 2014
ABSTRACT We completed this lab to classify and count phenotypic traits in plant crosses with one or two segregating mutations, and we also learned how to use the Chi-Square test as a tool to access the statistical significance data collected from a genetic cross. Our hypothesis for the experiment that included green and albino corn genetics, was that the ratio of green to albino seedlings would be 3:1. Our results showed that we were almost exactly right with that hypothesis. Our hypothesis for the analysis dihybrid cross in corn was that the ending ratio would be 9:3:3:1, our results drew close to that ratio. The last experiment …show more content…
After answering a series of questions about the seedlings, we statistically analyzed the data we collected. We constructed a chi-square test on our results from the corn seedling experiment and using the information from that we answered more questions.
For procedure 2, we were provided with a container of kernels that we classified and counted the F2 progeny and recorded the data. We sorted the seedlings into four different categories: yellow and round, yellow and wrinkled, purple and round, purple and wrinkled. Again we analyzed our data by using a chi-square test and answered questions about the data we collected. In procedure 3, we were given soybean plants, these plants grew to be a year old dropped their seeds, and their offspring grew for two weeks. We recorded the F2 generation by separating them by seedlings with dark green leafs, light green leafs, yellow leafs, green cotyledons, and yellow cotyledons. After our data was analyzed we used a chi-square test and answered more questions given to us about the data that we had …show more content…
There would be 75 green seedlings and 25 albino seedlings out of 100 seedlings. Our actual data ratio was 3.7:1 or 74 green seedlings to 20 albino seedlings. If the ratio was perfect it would have been 70.5 green seedlings to 23.5 Albino seedlings, which would have been a 3:1 ratio. The phenotypic and genotypic ratios were 3:1 dominant chlorophyll. In the 9:3:3:1 ratio counting corn we had 60 yellow round corn, 16 yellow and wrinkled, 16 purple and round, and 8 purple and wrinkled. Our hypothesis wasn’t exact to the 9:3:3:1 ratio but, it was close. We expected less for green seedlings and more for white seedlings in this experiment. The difference in the ratios was because we only had 94 plants to count instead of the exact number of 100 plants. In this experiment the albino plants were cc: or homozygous recessive, Cc was heterozygous, and CC was homozygous dominant. Even under the absolute perfect condition albino corn can only survive several weeks because they have a limited amount of chlorophyll to absorb light. We could not use these albino plants to produce more offspring because they have codoline, which means they only grow for a little bit because of starch.
What can help solve deviation in our experiments, is by using the Chi-Square test, which is illustrated in figure 2, 3, and 4. This is by using observed values, expected values, deviation, deviation 2, and the sum. After conducting the experiment
Trev Mumm and Peter Masinelli
Life 120 – Lab Section 122
April 28th, 2014
ABSTRACT We completed this lab to classify and count phenotypic traits in plant crosses with one or two segregating mutations, and we also learned how to use the Chi-Square test as a tool to access the statistical significance data collected from a genetic cross. Our hypothesis for the experiment that included green and albino corn genetics, was that the ratio of green to albino seedlings would be 3:1. Our results showed that we were almost exactly right with that hypothesis. Our hypothesis for the analysis dihybrid cross in corn was that the ending ratio would be 9:3:3:1, our results drew close to that ratio. The last experiment …show more content…
After answering a series of questions about the seedlings, we statistically analyzed the data we collected. We constructed a chi-square test on our results from the corn seedling experiment and using the information from that we answered more questions.
For procedure 2, we were provided with a container of kernels that we classified and counted the F2 progeny and recorded the data. We sorted the seedlings into four different categories: yellow and round, yellow and wrinkled, purple and round, purple and wrinkled. Again we analyzed our data by using a chi-square test and answered questions about the data we collected. In procedure 3, we were given soybean plants, these plants grew to be a year old dropped their seeds, and their offspring grew for two weeks. We recorded the F2 generation by separating them by seedlings with dark green leafs, light green leafs, yellow leafs, green cotyledons, and yellow cotyledons. After our data was analyzed we used a chi-square test and answered more questions given to us about the data that we had …show more content…
There would be 75 green seedlings and 25 albino seedlings out of 100 seedlings. Our actual data ratio was 3.7:1 or 74 green seedlings to 20 albino seedlings. If the ratio was perfect it would have been 70.5 green seedlings to 23.5 Albino seedlings, which would have been a 3:1 ratio. The phenotypic and genotypic ratios were 3:1 dominant chlorophyll. In the 9:3:3:1 ratio counting corn we had 60 yellow round corn, 16 yellow and wrinkled, 16 purple and round, and 8 purple and wrinkled. Our hypothesis wasn’t exact to the 9:3:3:1 ratio but, it was close. We expected less for green seedlings and more for white seedlings in this experiment. The difference in the ratios was because we only had 94 plants to count instead of the exact number of 100 plants. In this experiment the albino plants were cc: or homozygous recessive, Cc was heterozygous, and CC was homozygous dominant. Even under the absolute perfect condition albino corn can only survive several weeks because they have a limited amount of chlorophyll to absorb light. We could not use these albino plants to produce more offspring because they have codoline, which means they only grow for a little bit because of starch.
What can help solve deviation in our experiments, is by using the Chi-Square test, which is illustrated in figure 2, 3, and 4. This is by using observed values, expected values, deviation, deviation 2, and the sum. After conducting the experiment