Heartburn occurs when there is a painful feeling in the esophagus below the throat that leads to the stomach. Acid reflux can also be an issue if the hydrochloric acid in the stomach reaches the esophagus. One will hope to stay away from a more complex problem: GERD or gastro esophageal reflux disease (1). Bases can be extremely important to one’s health and wellness. Common bases include sodium hydroxide, sodium bicarbonate, sodium carbonate, and ammonia. They usually have a bitter taste and a slick feel. They can be used for a variety of things: NaHCO3 is an ingredient in baking soda. Not only are they used for food and health benefits, but bases are also used for manufacturing, production of products, and laundry detergents. The process of titration and back titration also needs to be discussed. The lab teacher assistant presented known concentrations but asked the students to find the unknown solution concentration in the experiment. The element in solution of unknown concentration would have to react with the element in solution of known concentration to find the amount of unknown concentration. The two known concentrations used in this experiment consisted of sodium hydroxide and hydrochloric …show more content…
However, the best three trials were used to calculate the average and the trials had to come within about 0.1 mL of each other. The following antacids were used: Gelusil, Alka Seltzer, Medifirst, and Alcalak tablets. The Alcalak was used for this specific group. The first trial came to be 11.3 mL NaOH and was converted to liters (L). The 0.0013 L was multiplied by 0.25 M NaOH to get 0.002825 moles of sodium hydroxide. The same calculation was performed for the second trial but the 0.25 M was multiplied by 11.45 mL or 0.01145 L to obtain 0.0028625 mol of NaOH. The third trial drew 12.6 mL or 0.0126 L of NaOH and was multiplied by 0.25 M to get 0.00315 moles. The fourth trial measured 13 ml and was converted to 0.013 L. The value for liters was multiplied by 0.25 M to get 0.0325 moles. The fifth and final trial was measured to be 10.5 mL or 0.0105 L and multiplied by 0.25 M to get 0.002625 moles of NaOH. The calculations were performed this way because the molarity was known and the amount of liters was found from the measurements. Molarity is the amount of moles of solute divided by liters of solution so this was the best way to find the moles. The top three trials were the first, second, and fifth for the Alcalak because they fell in the correct range. The results are shown in the following table and graph as well. The mole-to-mole ratio was 1:1 of NaOH to HCl in the experiment so each had the