Each distance was divided by time to get the speed in inches per second. Then the average of each was determined.
(5,692.8 inches/second)/(12 trials)=474.4 inches/second
(10,851.6 inches/second)/(12 trials)=904.3 inches/second 5,692.8 being the speeds of the softballs added up and 10,851.6 being the baseballs.
Average Softball Baseball
Speed (inches/second) 474.4 inches/second 904.3 …show more content…
vertex formula:y=a〖(x-h)〗^2+k In this equation, the a represents the change in slope in the parabola, the x being able to be substituted by the x coordinate of any point on the parabola, the h being the x coordinate of the vertex, the k being the y coordinate of the vertex, and the y being able to be substituted by the x coordinate of any point on the parabola.
Softball:
Vertex point: (0, 28)
Another point (the average distance of the softballs): (370.49, 0)
0=a(370.49)^2+28
a~-0.00020399 rounded
Making the equation y=-0.00020399x^2+28,x≥0. The greater than or equal to is present because the batter did not hit the ball away from the field of play and the starting point was at (0, 28) it was just reflected using the reflexive property.
Baseball:
Vertex point: (0, 28)
Another point (the average of the distance of baseballs): (410.98, 0)
0=a〖(410.98)〗^2+28
a ~-0.00016577 rounded
Making this equation y=-0.00016577x^2+28,x≥0. The same rule applies here for the